Back to Derivatives of inverse functions

Activity 2.6.3

Avg difficulty 2.5

The following prompts in this activity will lead you to develop the derivative of the inverse tangent function.

  1. Let r(x)=arctan⁡(x)r(x) = \arctan(x). Use the relationship between the arctangent and tangent functions to rewrite this equation using only the tangent function.

  2. Differentiate both sides of the equation you found in (a). Solve the resulting equation for r′(x)r'(x), writing r′(x)r'(x) as simply as possible in terms of a trigonometric function evaluated at r(x)r(x).

  3. Recall that r(x)=arctan⁡(x)r(x) = \arctan(x). Update your expression for r′(x)r'(x) so that it only involves trigonometric functions and the independent variable xx.

  4. Introduce a right triangle with angle θ\theta so that θ=arctan⁡(x)\theta = \arctan(x). What are the three sides of the triangle?

  5. In terms of only xx and 11, what is the value of cos⁡(arctan⁡(x))\cos(\arctan(x))?

  6. Use the results of your work above to find an expression involving only 11 and xx for r′(x)r'(x).

Boelkins, Active Calculus, §2.6 Derivatives of inverse functions, Activity 2.6.3

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Adapted from Active Calculus © 2012–2025 Matthew Boelkins. Licensed under CC BY-SA 4.0. Source: Active Calculus. Imported at revision dc86ba3.