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Exercise 8

Avg difficulty 2.5

A toy rocket is launched vertically from the ground on a day with no wind. The rocket's vertical velocity at time tt (in seconds) is given by v(t)=500−32tv(t)= 500-32t feet/sec.

  1. At what time after the rocket is launched does the rocket's velocity equal zero? Call this time value aa. What happens to the rocket at t=at = a?

  2. Find the value of the total area enclosed by y=v(t)y = v(t) and the tt-axis on the interval 0≤t≤a0 \le t \le a. What does this area represent in terms of the physical setting of the problem?

  3. Find an antiderivative ss of the function vv. That is, find a function ss such that s′(t)=v(t)s'(t) = v(t).

  4. Compute the value of s(a)−s(0)s(a) - s(0). What does this number represent in terms of the physical setting of the problem?

  5. Compute s(5)−s(1)s(5) - s(1). What does this number tell you about the rocket's flight?

Boelkins, Active Calculus, §4.1 Determining distance traveled from velocity, Exercise 8

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Adapted from Active Calculus © 2012–2025 Matthew Boelkins. Licensed under CC BY-SA 4.0. Source: Active Calculus. Imported at revision dc86ba3.