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Exercise 7

Avg difficulty 2.5

When an aircraft attempts to climb as rapidly as possible, its climb rate (in feet per minute) decreases as altitude increases, because the air is less dense at higher altitudes. Table provides performance data for a certain single engine aircraft, giving its climb rate at various altitudes, where c(h)c(h) denotes the climb rate of the airplane at an altitude hh.

Data for the climbing aircraft.
hh (feet)001000100020002000300030004000400050005000
cc (ft/min)925925875875830830780780730730685685
hh (feet)6000600070007000800080009000900010,00010{,}000
cc (ft/min)635635585585535535490490440440

Let a new function mm, that also depends on hh, (say y=m(h)y = m(h)) measure the number of minutes required for a plane at altitude hh to climb the next foot of altitude.

  1. Determine a similar table of values for m(h)m(h) and explain how it is related to the table above. Be sure to discuss the units on mm.

  2. Give a careful interpretation of a function whose derivative is m(h)m(h). Describe what the input is and what the output is. Also, explain in plain English what the function tells us.

  3. Determine a definite integral whose value tells us exactly the number of minutes required for the airplane to ascend to 10,000 feet of altitude. Clearly explain why the value of this integral has the required meaning.

  4. Determine a formula for a function M(h)M(h) whose value tells us the exact number of minutes required for the airplane to ascend to hh feet of altitude.

  5. Estimate the values of M(6000)M(6000) and M(10000)M(10000) as accurately as you can. Include units on your results.

Boelkins, Active Calculus, §5.2 The Second Fundamental Theorem of Calculus, Exercise 7

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Adapted from Active Calculus © 2012–2025 Matthew Boelkins. Licensed under CC BY-SA 4.0. Source: Active Calculus. Imported at revision dc86ba3.