Back to Other options for finding algebraic antiderivatives

Activity 5.5.2

Avg difficulty 2.5

For each of the following problems, evaluate the integral by using the partial fraction decomposition provided.

  1. ∫1x2−2x−3 dx\displaystyle \int \frac{1}{x^2 - 2x - 3} \, dx, given that 1x2−2x−3=1/4x−3−1/4x+1\displaystyle \frac{1}{x^2 - 2x - 3} = \frac{1/4}{x-3} - \frac{1/4}{x+1}

  2. ∫x2+1x3−x2 dx\displaystyle \int \frac{x^2+1}{x^3 - x^2} \, dx, given that x2+1x3−x2=−1x−1x2+2x−1\displaystyle \frac{x^2+1}{x^3 - x^2} = -\frac{1}{x} - \frac{1}{x^2} + \frac{2}{x-1}

  3. ∫x−2x4+x2 dx\displaystyle \int \frac{x-2}{x^4 + x^2}\, dx, given that x−2x4+x2=1x−2x2+−x+21+x2\displaystyle \frac{x-2}{x^4 + x^2} = \frac{1}{x} - \frac{2}{x^2} + \frac{-x+2}{1+x^2}

Boelkins, Active Calculus, §5.5 Other options for finding algebraic antiderivatives, Activity 5.5.2

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Adapted from Active Calculus © 2012–2025 Matthew Boelkins. Licensed under CC BY-SA 4.0. Source: Active Calculus. Imported at revision dc86ba3.