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Exercise 9

Avg difficulty 2.5

Consider the initial value problem dydt=−ty, y(0)=8\begin{gathered} \frac{dy}{dt} = -\frac ty, \ y(0) = 8 \end{gathered}

  1. Find the solution of the initial value problem and sketch its graph.

  2. For what values of tt is the solution defined?

  3. What is the value of yy at the last time that the solution is defined?

  4. By looking at the differential equation, explain why we should not expect to find solutions with the value of yy you noted in (c).

Boelkins, Active Calculus, §7.4 Separable differential equations, Exercise 9

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Adapted from Active Calculus © 2012–2025 Matthew Boelkins. Licensed under CC BY-SA 4.0. Source: Active Calculus. Imported at revision dc86ba3.