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Exercise 23

Avg difficulty 2.5

You might recall the pythagorean identity from trigonometry given by cos⁡2(θ)+sin⁡2(θ)=1\begin{gathered} \cos^2(\theta)+\sin^2(\theta)=1 \end{gathered} We want to use this identity to parameterize the circle with center (h,k)(h,k) and radius r>0r \gt 0 given by (x−h)2+(y−k)2=r2\begin{gathered} (x-h)^2 + (y-k)^2 = r^2 \end{gathered}

  1. Reorganize the general equation of a circle (x−h)2+(y−k)2=r2\begin{gathered} (x-h)^2 + (y-k)^2 = r^2 \end{gathered} to be of the form (‾)2+(‾)2=1\begin{gathered} (\underline{\hspace{2cm}})^2+(\underline{\hspace{2cm}})^2=1 \end{gathered}

  2. Because identities work for any value, we can use the pythagorean identity to parameterize the general equation of a circle. Fill in the blanks below with each of the respective quantities from the previous task cos⁡(t)=‾sin⁡(t)=‾\begin{aligned} \cos(t) = & \underline{\hspace{2cm}} \\ \sin(t) = & \underline{\hspace{2cm}} \end{aligned}

  3. Solve each of the two equations from the previous part for xx and yy to get parametric equations for a generalized circle.

  4. Write a couple sentences about what rr, hh, and kk mean in the parametric equations for a generalized circle.

Long, Keller & Schlicker, Active Calculus Multivariable, §10.2 Vector-Valued Functions of One Variable, Exercise 23

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Adapted from Active Calculus Multivariable © 2013–2026 Nicholas Long, Mitchel T. Keller, and Steven Schlicker. Licensed under CC BY-SA 4.0. Source: Active Calculus Multivariable. Imported at revision 692c03c.