Back to Vector-Valued Functions of One Variable

Exercise 26

Avg difficulty 2.5

In this exercise, we will examine the graph of z=3x2+4y2−2z = 3x^2 + 4y^2 - 2. You do not need to know what this graph looks like, but we will look at the intersection of this graph with several types of fundamental planes.

  1. Determine a vector-valued function r⃗\vr that parameterizes the curve which is the x=2x = 2 trace of z=3x2+4y2−2z = 3x^2 + 4y^2 - 2. Plot the resulting curve. Do likewise for x=−2,−1,0,x = -2, -1, 0, and 11.

  2. Determine a vector-valued function r⃗\vr that parameterizes the curve which is the y=2y = 2 trace of z=3x2+4y2−2z = 3x^2 + 4y^2 - 2. Plot the resulting curve. Do likewise for y=−2,−1,0,y = -2, -1, 0, and 11.

  3. Determine a vector-valued function r⃗\vr that parameterizes the curve which is the z=2z = 2 contour of z=3x2+4y2−2z = 3x^2 + 4y^2 - 2. Plot the resulting curve. Do likewise for z=−2,−1,0,z = -2, -1, 0, and 11.

  4. Use the traces and contours you've just investigated to create a wireframe plot of the surface generated by z=3x2+4y2−2z = 3x^2 + 4y^2 - 2. In addition, write a couple sentences to describe the characteristics of the surface.

Long, Keller & Schlicker, Active Calculus Multivariable, §10.2 Vector-Valued Functions of One Variable, Exercise 26

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Adapted from Active Calculus Multivariable © 2013–2026 Nicholas Long, Mitchel T. Keller, and Steven Schlicker. Licensed under CC BY-SA 4.0. Source: Active Calculus Multivariable. Imported at revision 692c03c.