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Activity 10.6.2

Avg difficulty 2.5

In this activity we will use our previous work in finding unit speed parameterizations of lines and circles to make sense of the definition of curvature.

  1. Recall that in this example we found that the unit speed parameterization of a line through the points (1,2,3)(1,2,3) and (2,0,5)(2,0,5) to be r⃗1(s)=⟨1,2,3⟩+s3⟨1,−2,2⟩\vr_1(s)= \langle 1,2,3\rangle + \frac{s}{3} \langle 1,-2,2 \rangle. Calculate T⃗(s)\vT(s), dT⃗ds\frac{d\vT}{ds}, and ∥dT⃗ds∥\vecmag{ \frac{d\vT}{ds} } for the unit speed parameterization of this line. Note that because we are using the unit speed parameterization, our parameter tt is the same as the arc length traveled ss. In other words, t=st=s for this parameterization.

  2. Write a few sentences to explain why your result for the calculation of the curvature κ=∥dT⃗ds∥\kappa=\vecmag{ \frac{d\vT}{ds} } for this line makes sense. this exercise asks you to do the calculations to confirm this property of an arbitrary line.

  3. Recall from this activity have a parameterization of a circle in 2-space of radius RR centered at the origin as ⟨Rcos⁡(t),Rsin⁡(t)⟩\langle R\cos(t),R\sin(t)\rangle. A quick calculation will verify that this parameterization has constant speed and that speed is RR.

    Modifying this parameterization by multiplying the parameter by 1speed=1R\frac{1}{\text{speed}}=\frac{1}{R} gives the following parameterization: r⃗(s)=⟨Rcos⁡(sR),Rsin⁡(sR)⟩\begin{gathered} \vr(s) = \left\langle R \cos\left(\frac{s}{R}\right), R \sin\left(\frac{s}{R}\right)\right\rangle \end{gathered} Compute the speed of this parameterization to verify that this has unit speed. This will also show that r⃗ ′(s)=v⃗(s)=T⃗(s)\vr\, '(s)=\vv(s)=\vT(s). (Recall that this fact is not true in general!)

  4. Calculate T⃗(s)\vT(s), dT⃗ds\frac{d\vT}{ds}, and ∥dT⃗ds∥\vecmag{ \frac{d\vT}{ds} } for the unit speed parameterization of a circle of radius RR centered at the origin.

  5. Write a few sentences to explain why your result for the calculation of κ=∥dT⃗ds∥\kappa=\vecmag{ \frac{d\vT}{ds} } of circle will be constant. You should also address why circles with larger radii will have have smaller curvature.

Long, Keller & Schlicker, Active Calculus Multivariable, §10.6 Curvature, Activity 10.6.2

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Adapted from Active Calculus Multivariable © 2013–2026 Nicholas Long, Mitchel T. Keller, and Steven Schlicker. Licensed under CC BY-SA 4.0. Source: Active Calculus Multivariable. Imported at revision 692c03c.