Back to Linearization: Tangent Planes and Differentials

Exercise 30

Avg difficulty 2.5

We know that if a function of a single variable is differentiable at a point, then that function is also continuous at that point. In this exercise we determine that the same property holds for functions of two variables. A function ff of the two variables xx and yy is continuous at a point (x0,y0)(x_0,y_0) in its domain if lim⁡(x,y)→(x0,y0)f(x,y)=f(x0,y0)\begin{gathered} \lim_{(x,y) \to (x_0,y_0)} f(x,y) = f(x_0,y_0) \end{gathered} or (letting x=x0+hx=x_0+h and y=y0+ky = y_0 + k, lim⁡(h,k)→(0,0)f(x0+h,y+k)=f(x0,y0).\begin{gathered} \lim_{(h,k) \to (0,0)} f(x_0+h,y+k) = f(x_0,y_0). \end{gathered} Show that if ff is differentiable at (x0,y0)(x_0,y_0), then ff is continuous at (x0,y0)(x_0,y_0). (Hint: Multiply both sides of the equality that comes from differentiability by lim⁡(h,k)→(0,0)h2+k2\lim_{(h,k) \to (0,0)} \sqrt{h^2+k^2}.)

Long, Keller & Schlicker, Active Calculus Multivariable, §11.6 Linearization: Tangent Planes and Differentials, Exercise 30

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Adapted from Active Calculus Multivariable © 2013–2026 Nicholas Long, Mitchel T. Keller, and Steven Schlicker. Licensed under CC BY-SA 4.0. Source: Active Calculus Multivariable. Imported at revision 692c03c.