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Exercise 28

Avg difficulty 2.5

Consider the solid that lies between the paraboloids z=g(x,y)=x2+y2z = g(x,y) = x^2 + y^2 and z=f(x,y)=8−3x2−3y2z = f(x,y) = 8 - 3x^2 - 3y^2.

  1. By eliminating the variable zz, determine the curve of intersection between the two paraboloids, and sketch this curve in the xyxy-plane.

  2. Set up, but do not evaluate, an iterated integral expression whose value determines the mass of the solid, integrating first with respect to zz, then yy, then xx. Assume the the solid's density is given by δ(x,y,z)=1x2+y2+z2+1\delta(x,y,z) = \frac{1}{x^2 + y^2 + z^2 + 1}.

  3. Set up, but do not evaluate, iterated integral expressions whose values determine the mass of the solid using all possible remaining orders of integration. Use δ(x,y,z)=1x2+y2+z2+1\delta(x,y,z) = \frac{1}{x^2 + y^2 + z^2 + 1} as the density of the solid.

  4. Set up, but do not evaluate, iterated integral expressions whose values determine the center of mass of the solid. Again, assume the the solid's density is given by δ(x,y,z)=1x2+y2+z2+1\delta(x,y,z) = \frac{1}{x^2 + y^2 + z^2 + 1}.

  5. Which coordinates of the center of mass can you determine without evaluating any integral expression? Why?

Long, Keller & Schlicker, Active Calculus Multivariable, §12.7 Triple Integrals, Exercise 28

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Adapted from Active Calculus Multivariable © 2013–2026 Nicholas Long, Mitchel T. Keller, and Steven Schlicker. Licensed under CC BY-SA 4.0. Source: Active Calculus Multivariable. Imported at revision 692c03c.