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Activity 13.12.2

Avg difficulty 2.5

In this activity, we will try to understand the scalar surface integral by looking at whether the value of the scalar surface integral will be positive, negative, or zero over common surfaces. In each part below, you are given a function and a surface. For each surface, first draw a plot of the surface and make sure you have labeled a proper scale for each coordinate direction. Then reason if the given surface integral is positive, negative, or zero. Be sure to justify your answers in terms of the function being integrated and the particulars of the surface of integration.

  1. For S1S_1 defined as the top half (z≥0z \geq 0) of the sphere of radius one centered at the origin, consider the surface integral ∬S1x dS\iint_{S_1} x \, dS.

  2. For S2S_2 defined as the bottom half (z≤0z \leq 0) of the sphere of radius one centered at the origin, consider the surface integral ∬S2z dS\iint_{S_2} z \, dS.

  3. For S3S_3 defined as the disc of radius one centered at (1,0,0)(1,0,0) on the plane x=1x=1, consider the surface integral ∬S3x+z dS\iint_{S_3} x+z \, dS.

  4. For S1S_1 as defined above, consider the surface integral ∬S1x+z dS\iint_{S_1} x+z \, dS.

Long, Keller & Schlicker, Active Calculus Multivariable, §13.12 Surface Integrals of Scalar Valued Functions, Activity 13.12.2

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Adapted from Active Calculus Multivariable © 2013–2026 Nicholas Long, Mitchel T. Keller, and Steven Schlicker. Licensed under CC BY-SA 4.0. Source: Active Calculus Multivariable. Imported at revision 692c03c.