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Exercise 9

Avg difficulty 2.5

(A challenging problem) For each formula, give both a proof using the Principle of Mathematical Induction and a combinatorial proof. One of the two will be easier while the other will be more challenging.

  1. 12+22+32+⋯+n2=n(n+1)(2n+1)6\displaystyle 1^2+2^2+3^2+\dots+ n^2= \frac{n(n+1)(2n+1)}{6}

  2. (n0)20+(n1)21+(n2)22+⋯+(nn)2n=3n\displaystyle\binom{n}{0}2^0+\binom{n}{1}2^1+\binom{n}{2}2^2+\dots+\binom{n}{n}2^n=3^n

Keller & Trotter, Applied Combinatorics, Induction — Exercises, Exercise 9

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Adapted from Applied Combinatorics © 2006–2025 Mitchel T. Keller, William T. Trotter. Licensed under CC BY-SA 4.0. Source: Applied Combinatorics. Imported at revision 07286c4.