5.3 Exercise 17 — Applied Probability

The data of the exercise, above, are converted to conditional probabilities and probabilities, as follows (probabilities are rounded to two decimal places).

GROUP 1 $P \left(G_{1}\right) = 0 . 56$	GROUP 2 $P \left(G_{2}\right) = 0 . 44$
Q	Yes	No	Unc	Yes	No	Unc
1	0.61	0.31	0.08	0.41	0.51	0.08
2	0.50	0.38	0.12	0.29	0.65	0.06
3	0.23	0.64	0.13	0.59	0.33	0.08
4	0.29	0.63	0.08	0.57	0.29	0.14
5	0.32	0.62	0.06	0.42	0.50	0.08
6	0.58	0.23	0.19	0.29	0.62	0.09
7	0.19	0.70	0.11	0.56	0.32	0.12
8	0.56	0.38	0.06	0.29	0.63	0.08
9	0.65	0.20	0.15	0.41	0.50	0.09
10	0.29	0.63	0.08	0.59	0.32	0.09

For the following profiles classify each individual in one of the subgroups.

y, n, y, n, y, u, n, u, y, u
n, n, u, n, y, y, u, n, n, y
y, y, n, y, u, u, n, n, y, y

Pfeiffer, Applied Probability, 5.3 Problems on Conditional Independence, exercise 17

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