Back to 6.2 Problems on Random Variables and Probabilities

6.2 Exercise 17

Avg difficulty 2.5

A marker is placed at a reference position on a line (taken to be the origin); a coin is tossed repeatedly. If a head turns up, the marker is moved one unit to the right; if a tail turns up, the marker is moved one unit to the left.

  1. Show that the position at the end of ten tosses is given by the random variable
    X=∑i=110IEi-∑i=110IEic=2∑i=110IEi-10=2S10-10X = \sum_{i = 1}^{10} I_{E_{i}} - \sum_{i = 1}^{10} I_{E_{i}^{c}} = 2 \sum_{i = 1}^{10} I_{E_{i}} - 10 = 2 S_{10} - 10
    where Ei is the event of a head on the ith toss and S10 is the number of heads in ten trials.
  2. After ten tosses, what are the possible positions and the probabilities of being in each?

Pfeiffer, Applied Probability, 6.2 Problems on Random Variables and Probabilities, exercise 17

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Adapted from Applied Probability © 2009 Paul E. Pfeiffer. Licensed under CC BY 3.0. Source: Applied Probability. Imported at revision d7a0420.