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12.4 Exercise 158

Avg difficulty 2.5

Use technology to evaluate the limit.

Evaluate the limit by hand.

lim x→1 f(x), where  f(x)={ 4x−7 x≠1 x 2 −4 x=1 \begin{matrix}\lim \\ ^{x \rightarrow 1}\end{matrix} f \left(x\right) , \textrm{ }\text{where}\textrm{ }\textrm{ } f \left(x\right) = \left\{\right. \begin{matrix}4 x - 7 & x \neq 1 \\ x^{2} - 4 & x = 1\end{matrix}

At what value(s) of x x is the function below discontinuous?

f(x)={ 4x−7x≠1 x 2 −4x=1 f \left(x\right) = \left\{\right. \begin{matrix}4 x - 7 x \neq 1 \\ x^{2} - 4 x = 1\end{matrix}

OpenStax Precalculus 2e, 12.4 Derivatives, exercise 158

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Adapted from College Algebra © 2021 Rice University. Licensed under CC BY 4.0. Sources: College Algebra 2e, Algebra and Trigonometry 2e, Precalculus 2e, College Algebra with Corequisite Support 2e. Imported at revision 4922e46.