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Back to 11.7 Solving Systems with Inverses

11.7 Exercise 60

Avg difficulty 2.5

Solve a system using the inverse of a 3×3 3 \times 3 matrix.

1 2 x− 1 5 y+ 1 5 z= 31 100 − 3 4 x− 1 4 y+ 1 2 z= 7 40 − 4 5 x− 1 2 y+ 3 2 z= 1 4 \begin{matrix}\frac{1}{2} x - \frac{1}{5} y + \frac{1}{5} z = \frac{31}{100} \\ - \frac{3}{4} x - \frac{1}{4} y + \frac{1}{2} z = \frac{7}{40} \\ - \frac{4}{5} x - \frac{1}{2} y + \frac{3}{2} z = \frac{1}{4}\end{matrix}

OpenStax Algebra and Trigonometry 2e, 11.7 Solving Systems with Inverses, exercise 60

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Adapted from College Algebra © 2021 Rice University. Licensed under CC BY 4.0. Sources: College Algebra 2e, Algebra and Trigonometry 2e, Precalculus 2e, College Algebra with Corequisite Support 2e. Imported at revision 4922e46.