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19.2 Exercise 14

Avg difficulty 2.5

The electric field strength between two parallel conducting plates separated by 4.00 cm is 7.50×104 V/m7 . \text{50} \times \text{10}^{4} \text{ V}/\text{m}. (a) What is the potential difference between the plates? (b) The plate with the lowest potential is taken to be at zero volts. What is the potential 1.00 cm from that plate (and 3.00 cm from the other)?

OpenStax College Physics 2e, 19.2 Electric Potential in a Uniform Electric Field, exercise 14

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Adapted from College Physics © 2022 Rice University. Licensed under CC BY 4.0. Sources: College Physics 2e, College Physics for AP® Courses 2e. Imported at revision f98d7a7.