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5.1 Exercise 24

Avg difficulty 2.5

A freight train consists of two 8.00×105-kg8 . \text{00} \times \text{10}^{5} -\text{kg} engines and 45 cars with average masses of 5.50×105 kg5 . \text{50} \times \text{10}^{5} \text{ kg}. (a) What force must each engine exert backward on the track to accelerate the train at a rate of 5.00×10−2m/s25 . \text{00} \times \text{10}^{- 2} m / s^{2} if the force of friction is 7.50×105N7 . \text{50} \times \text{10}^{5} N, assuming the engines exert identical forces? This is not a large frictional force for such a massive system. Rolling friction for trains is small, and consequently trains are very energy-efficient transportation systems. (b) What is the magnitude of the force in the coupling between the 37th and 38th cars (this is the force each exerts on the other), assuming all cars have the same mass and that friction is evenly distributed among all of the cars and engines?

OpenStax College Physics 2e, 5.1 Friction, exercise 24

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Adapted from College Physics © 2022 Rice University. Licensed under CC BY 4.0. Sources: College Physics 2e, College Physics for AP® Courses 2e. Imported at revision f98d7a7.