Back to 32.6 Fission

32.6 Exercise 15

Avg difficulty 2.5

(a) Calculate the energy released in the neutron-induced fission reaction

n+ 239Pu→ 96Sr+ 140Ba+4n,n + ^{\text{239}} \text{Pu} \rightarrow ^{\text{96}} \text{Sr} + ^{\text{140}} \text{Ba} + 4 n ,

given m(96Sr)=95.921750 um \left(\right. ^{\text{96}} \text{Sr} \left.\right) = \text{95} . \text{921750 u} and m(140Ba)=139.910581 um \left(\right. ^{\text{140}} \text{Ba} \left.\right) = \text{139} . \text{910581 u}.

(b) Confirm that the total number of nucleons and total charge are conserved in this reaction.

OpenStax College Physics 2e, 32.6 Fission, exercise 15

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Adapted from College Physics © 2022 Rice University. Licensed under CC BY 4.0. Sources: College Physics 2e, College Physics for AP® Courses 2e. Imported at revision f98d7a7.