16.4 Exercise 12

As usual, the acceleration due to gravity in these problems is taken to be $g = 9.80 \text{m} / \text{s}^{2}$, unless otherwise specified.

(a) A pendulum that has a period of 3.00000 s and that is located where the acceleration due to gravity is $9 . \text{79} \text{m}/\text{s}^{2}$ is moved to a location where the acceleration due to gravity is $9 . \text{82} \text{m}/\text{s}^{2}$. What is its new period? (b) Explain why so many digits are needed in the value for the period, based on the relation between the period and the acceleration due to gravity.