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3.4 Exercise 30

Avg difficulty 2.5

Derive R=v02sin2θ0gR = \frac{v_{0}^{2} \text{sin} 2θ_{0}}{g} for the range of a projectile on level ground by finding the time tt at which yy becomes zero and substituting this value of tt into the expression for x−x0x - x_{0}, noting that R=x−x0R = x - x_{0}

OpenStax College Physics 2e, 3.4 Projectile Motion, exercise 30

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Adapted from College Physics © 2022 Rice University. Licensed under CC BY 4.0. Sources: College Physics 2e, College Physics for AP® Courses 2e. Imported at revision f98d7a7.