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Back to 7.8 The Addition Rule for Probability

7.8 Exercise 5

Avg difficulty 2.5

Suppose we have events EE, FF, and GG, associated with these probabilities:

P(E)=0.45P(F)=0.6P(G)=0.55P(Eand⁢F)=0.2P(Eand⁢G)=0.2P(Fand⁢G)=0.25\begin{aligned}P \left(E\right) & = & 0.45 \\ P \left(F\right) & = & 0.6 \\ P \left(G\right) & = & 0.55 \\ P \left(E \text{and} F\right) & = & 0.2 \\ P \left(E \text{and} G\right) & = & 0.2 \\ P \left(F \text{and} G\right) & = & 0.25\end{aligned}

Compute the following:

  1. P(E⁢or⁢F)P \left(E \text{or} F\right)
  2. P(E⁢or⁢G)P \left(E \text{or} G\right)
  3. P(F⁢or⁢G)P \left(F \text{or} G\right)

OpenStax Contemporary Mathematics, 7.8 The Addition Rule for Probability, exercise 5

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Adapted from Contemporary Mathematics © 2023 Rice University. Licensed under CC BY 4.0. Source: Contemporary Mathematics. Imported at revision fa7c1a1.