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Exercise 101

Avg difficulty 2.5

Find the general solution to [100020003]x⃗ ′′=[−3002−4006−3]x⃗+[cos⁡(2t)00]\left[ \begin{smallmatrix} 1 & 0 & 0\\ 0 & 2 & 0\\ 0 & 0 & 3 \end{smallmatrix}\right] \vec{x}\,'' = \left[ \begin{smallmatrix} -3 & 0 & 0 \\ 2 & -4 & 0 \\ 0 & 6 & -3 \end{smallmatrix}\right] \vec{x} + \left[ \begin{smallmatrix} \cos(2t) \\ 0 \\ 0 \end{smallmatrix}\right].

Lebl, Notes on Diffy Qs, §3.6 Second-order systems and applications, exercise 101

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Adapted from Notes on Diffy Qs © 2008–2026 Jiří Lebl. Licensed under CC BY-SA 4.0. Source: Notes on Diffy Qs: Differential Equations for Engineers. Imported at revision 658bcae.