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Exercise 1

Avg difficulty 2.5

Find the first five terms of the sequence {an}\{a_n\}, beginning with n=0n=0:

  1. an=2n+3a_n = 2^n + 3
  2. an=nn+1a_n = n^{n+1}
  3. an=⌊n/2⌋+⌈n/2⌉a_n = \lfloor n/2\rfloor + \lceil n/2 \rceil
  4. an=6an−1,a0=2a_n = 6a_{n-1},\hspace{1em} a_0 = 2
  5. an=an−1+3an−2,a0=1,a1=2a_n = a_{n-1} + 3 a_{n-2},\hspace{1em} {a_0 = 1, a_1 = 2}

Hammond, Discrete Math for Shockers, §4.1 Sequences and Series, Exercise 1

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Adapted from Discrete Math for Shockers © 2021 John Hammond. Licensed under CC BY-SA 4.0. Source: Discrete Math for Shockers. Imported at revision 2538beb.