Back to Induction

Exercise 12

Avg difficulty 2.5

What is wrong with the following “proof” of the “fact” that n+3=n+7n+3 = n+7 for all values of nn (besides of course that the thing it is claiming to prove is false)?

Let P(n)P(n) be the statement that n+3=n+7n + 3 = n + 7. We will prove that P(n)P(n) is true for all n∈Nn \in \N. Assume, for induction that P(k)P(k) is true. That is, k+3=k+7k+3 = k+7. We must show that P(k+1)P(k+1) is true. Now since k+3=k+7k + 3 = k + 7, add 1 to both sides. This gives k+3+1=k+7+1k + 3 + 1 = k + 7 + 1. Regrouping (k+1)+3=(k+1)+7(k+1) + 3 = (k+1) + 7. But this is simply P(k+1)P(k+1). Thus by the principle of mathematical induction P(n)P(n) is true for all n∈Nn \in \N.

Levin, Discrete Mathematics: An Open Introduction (3rd ed.), §3.5 Induction, Exercise 12

AI Tutor

Adapted from Discrete Mathematics: An Open Introduction © 2013–2019 Oscar Levin. Licensed under CC BY-SA 4.0. Source: Discrete Mathematics: An Open Introduction. Imported at revision 1e2e26b.