Back to Propositional Logic

Exercise 16

Avg difficulty 2.5

We can also simplify statements in predicate logic using our rules for passing negations over quantifiers, and then applying propositional logical equivalence to the “inside” propositional part. Simplify the statements below (so negation appears only directly next to predicates).

  1. ¬∃x∀y(¬O(x)∨E(y))\neg \exists x \forall y (\neg O(x) \vee E(y)).
  2. ¬∀x¬∀y¬(x<y∧∃z(x<z∨y<z))\neg \forall x \neg \forall y \neg(x \lt y \wedge \exists z (x \lt z \vee y \lt z)).
  3. There is a number nn for which no other number is either less nn than or equal to nn.

  4. It is false that for every number nn there are two other numbers which nn is between.

Levin, Discrete Mathematics: An Open Introduction (3rd ed.), §4.1 Propositional Logic, Exercise 16

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Adapted from Discrete Mathematics: An Open Introduction © 2013–2019 Oscar Levin. Licensed under CC BY-SA 4.0. Source: Discrete Mathematics: An Open Introduction. Imported at revision 1e2e26b.