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Exercise 6

Avg difficulty 3.0

Solve each system using matrix notation. Express the solution set using vectors.

  • (a)  3x+2y+z=1x−y+z=25x+5y+z=0\begin{array}{rcrcrcr}3x&+&2y&+&z&=&1\\ x&-&y&+&z&=&2\\ 5x&+&5y&+&z&=&0\end{array}     (b)  x+y−2z=0x−y=−33x−y−2z=−62y−2z=3\begin{array}{rcrcrcrcr}x&+&y&-&2z&=&0\\ x&-&y&&&=&-3\\ 3x&-&y&-&2z&=&-6\\ &&2y&-&2z&=&3\end{array}     (c)  2x−y−z+w=4x+y+z=−1\begin{array}{rcrcrcrcrcr}2x&-&y&-&z&+&w&=&4\\ x&+&y&+&z&&&=&-1\end{array}     (d)  x+y−2z=0x−y=−33x−y−2z=0\begin{array}{rcrcrcr}x&+&y&-&2z&=&0\\ x&-&y&&&=&-3\\ 3x&-&y&-&2z&=&0\end{array}

Hefferon, Linear Algebra, Linear Systems, Describing the Solution Set, Exercise 6

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Adapted from Linear Algebra © 2016 Jim Hefferon. Licensed under CC BY-SA 3.0 US. Source: Linear Algebra. Imported at revision df2262e.