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Back to Gauss-Jordan Reduction

Exercise 1

Avg difficulty 3.0

Use Gauss-Jordan reduction to solve each system.

  • (a)  x+y=2x−y=0\begin{array}{rcrcr}x&+&y&=&2\\ x&-&y&=&0\end{array}     (b)  x−z=42x+2y=1\begin{array}{rcrcrcr}x&&&-&z&=&4\\ 2x&+&2y&&&=&1\end{array}     (c)  3x−2y=16x+y=1/2\begin{array}{rcrcr}3x&-&2y&=&1\\ 6x&+&y&=&1/2\end{array}     (d)  2x−y=−1x+3y−z=5y+2z=5\begin{array}{rcrcrcr}2x&-&y&&&=&-1\\ x&+&3y&-&z&=&5\\ &&y&+&2z&=&5\end{array}

Hefferon, Linear Algebra, Linear Systems, Gauss-Jordan Reduction, Exercise 1

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Adapted from Linear Algebra © 2016 Jim Hefferon. Licensed under CC BY-SA 3.0 US. Source: Linear Algebra. Imported at revision df2262e.