Back to Gauss’s Method

Exercise 2

Avg difficulty 3.0

Each system is in echelon form. For each, say whether the system has a unique solution, no solution, or infinitely many solutions.

  • (a)  −3x+2y=0−2y=0\begin{array}{rcrcr}-3x&+&2y&=&0\\ &&-2y&=&0\end{array}     (b)  x+y=4y−z=0\begin{array}{rcrcrcr}x&+&y&&&=&4\\ &&y&-&z&=&0\\ \end{array}     (c)  x+y=4y−z=00=0\begin{array}{rcrcrcr}x&+&y&&&=&4\\ &&y&&-z&=&0\\ &&&&0&=&0\end{array}     (d)  x+y=40=4\begin{array}{rcrcr}x&+&y&=&4\\ &&0&=&4\end{array}     (e)  3x+6y+z=−0.5−z=2.5\begin{array}{rcrcrcr}3x&+&6y&+&z&=&-0.5\\ &&&&-z&=&2.5\\ \end{array}     (f)  x−3y=20=0\begin{array}{rcrcr}x&-&3y&=&2\\ &&0&=&0\end{array}     (g)  2x+2y=4y=10=4\begin{array}{rcrcr}2x&+&2y&=&4\\ &&y&=&1\\ &&0&=&4\end{array}     (h)  2x+y=0\begin{array}{rcrcr}2x&+&y&=&0\end{array}     (i)  x−y=−10=00=4\begin{array}{rcrcr}x&-&y&=&-1\\ &&0&=&0\\ &&0&=&4\end{array}     (j)  x+y−3z=−1y−z=2z=00=0\begin{array}{rcrcrcr}x&+&y&-&3z&=&-1\\ &&y&-&z&=&2\\ &&&&z&=&0\\ &&&&0&=&0\end{array}

Hefferon, Linear Algebra, Linear Systems, Gauss’s Method, Exercise 2

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Adapted from Linear Algebra © 2016 Jim Hefferon. Licensed under CC BY-SA 3.0 US. Source: Linear Algebra. Imported at revision df2262e.