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Exercise 11

Avg difficulty 3.0

Prove or disprove that R3\mathbb{R}^{3} is a vector space under these operations.

  • (x1y1z1)+(x2y2z2)=(000)andr(xyz)=(rxryrz)\begin{pmatrix}x_{1}\\ y_{1}\\ z_{1}\end{pmatrix}+\begin{pmatrix}x_{2}\\ y_{2}\\ z_{2}\end{pmatrix}=\begin{pmatrix}0\\ 0\\ 0\end{pmatrix}\quad\text{and}\quad r\begin{pmatrix}x\\ y\\ z\end{pmatrix}=\begin{pmatrix}rx\\ ry\\ rz\end{pmatrix}

  • (x1y1z1)+(x2y2z2)=(000)andr(xyz)=(000)\begin{pmatrix}x_{1}\\ y_{1}\\ z_{1}\end{pmatrix}+\begin{pmatrix}x_{2}\\ y_{2}\\ z_{2}\end{pmatrix}=\begin{pmatrix}0\\ 0\\ 0\end{pmatrix}\quad\text{and}\quad r\begin{pmatrix}x\\ y\\ z\end{pmatrix}=\begin{pmatrix}0\\ 0\\ 0\end{pmatrix}

Hefferon, Linear Algebra, Vector Spaces, Definition and Examples, Exercise 11

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Adapted from Linear Algebra © 2016 Jim Hefferon. Licensed under CC BY-SA 3.0 US. Source: Linear Algebra. Imported at revision df2262e.