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Exercise 6

Avg difficulty 3.0

Show that each of these is not a vector space. (Hint. Check closure by listing two members of each set and trying some operations on them.)

  • Under the operations inherited from R3\mathbb{R}^{3}, this set

    {(xyz)∈R3∣x+y+z=1}\{\hskip 1.00006pt\begin{pmatrix}x\\ y\\ z\end{pmatrix}\in\mathbb{R}^{3}\mid x+y+z=1\hskip 1.00006pt\}
  • Under the operations inherited from R3\mathbb{R}^{3}, this set

    {(xyz)∈R3∣x2+y2+z2=1}\{\hskip 1.00006pt\begin{pmatrix}x\\ y\\ z\end{pmatrix}\in\mathbb{R}^{3}\mid x^{2}+y^{2}+z^{2}=1\hskip 1.00006pt\}
  • Under the usual matrix operations,

    {(a1bc)∣a,b,c∈R}\{\hskip 1.00006pt\begin{pmatrix}a&1\\ b&c\end{pmatrix}\mid a,b,c\in\mathbb{R}\hskip 1.00006pt\}
  • Under the usual polynomial operations,

    {a0+a1x+a2x2∣a0,a1,a2∈R+}\{\hskip 1.00006pta_{0}+a_{1}x+a_{2}x^{2}\mid a_{0},a_{1},a_{2}\in\mathbb{R}^{+}\hskip 1.00006pt\}

    where R+\mathbb{R}^{+} is the set of reals greater than zero

  • Under the inherited operations,

    {(xy)∈R2∣x+3y=4 and 2x−y=3 and 6x+4y=10}\{\hskip 1.00006pt\begin{pmatrix}x\\ y\end{pmatrix}\in\mathbb{R}^{2}\mid\text{$x+3y=4$ and $2x-y=3$ and $6x+4y=10$}\hskip 1.00006pt\}

Hefferon, Linear Algebra, Vector Spaces, Definition and Examples, Exercise 6

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Adapted from Linear Algebra © 2016 Jim Hefferon. Licensed under CC BY-SA 3.0 US. Source: Linear Algebra. Imported at revision df2262e.