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Exercise 2

Avg difficulty 3.0

Find a basis for, and the dimension of, the solution set of this system.

x1−4x2+3x3−x4=02x1−8x2+6x3−2x4=0\begin{array}{rcrcrcrcr}x_{1}&-&4x_{2}&+&3x_{3}&-&x_{4}&=&0\\ 2x_{1}&-&8x_{2}&+&6x_{3}&-&2x_{4}&=&0\end{array}

Hefferon, Linear Algebra, Vector Spaces, Dimension, Exercise 2

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Adapted from Linear Algebra © 2016 Jim Hefferon. Licensed under CC BY-SA 3.0 US. Source: Linear Algebra. Imported at revision df2262e.