Back to Dimensional Analysis

Exercise 5

Avg difficulty 3.0

Prove that the dimensionless products form a vector space under the +⃗\vec{+} operation of multiplying two such products and the ⋅⃗\vec{\cdot} operation of raising such the product to the power of the scalar. (The vector arrows are a precaution against confusion.) That is, prove that, for any particular homogeneous system, this set of products of powers of m1m_{1}, …, mkm_{k}

{m1p1…mkpk∣p1, …, pk satisfy the system}\{\hskip 1.00006ptm_{1}^{p_{1}}\dots m_{k}^{p_{k}}\mid\text{$p_{1}$, \ldots, $p_{k}$ satisfy the system}\hskip 1.00006pt\}

is a vector space under:

m1p1…mkpk+⃗m1q1…mkqk=m1p1+q1…mkpk+qkm_{1}^{p_{1}}\dots m_{k}^{p_{k}}\vec{+}m_{1}^{q_{1}}\dots m_{k}^{q_{k}}=m_{1}^{p_{1}+q_{1}}\dots m_{k}^{p_{k}+q_{k}}

and

r⋅⃗(m1p1…mkpk)=m1rp1…mkrpkr\vec{\cdot}(m_{1}^{p_{1}}\dots m_{k}^{p_{k}})=m_{1}^{rp_{1}}\dots m_{k}^{rp_{k}}

(assume that all variables represent real numbers).

Hefferon, Linear Algebra, Vector Spaces, Dimensional Analysis, Exercise 5

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Adapted from Linear Algebra © 2016 Jim Hefferon. Licensed under CC BY-SA 3.0 US. Source: Linear Algebra. Imported at revision df2262e.