Back to Projection Into a Subspace

Exercise 19

Avg difficulty 3.0

Define a projection to be a linear transformation t ⁣:V→Vt\colon V\to V with the property that repeating the projection does nothing more than does the projection alone: (t∘t) (v⃗)=t(v⃗)(t\mathbin{\circ}t)\,(\vec{v})=t(\vec{v}) for all v⃗∈V\vec{v}\in V.

  • Show that orthogonal projection into a line has that property.

  • Show that projection along a subspace has that property.

  • Show that for any such tt there is a basis B=⟨β⃗1,…,β⃗n⟩B=\langle\vec{\beta}_{1},\ldots,\vec{\beta}_{n}\rangle for VV such that

    t(β⃗i)={β⃗ii=1,2,…, r0⃗i=r+1,r+2,…, nt(\vec{\beta}_{i})=\begin{cases}\vec{\beta}_{i}&i=1,2,\dots,\,r\\ \vec{0}&i=r+1,r+2,\dots,\,n\end{cases}

    where rr is the rank of tt.

  • Conclude that every projection is a projection along a subspace.

  • Also conclude that every projection has a representation

    RepB,B(t)=(IZZZ){\rm Rep}_{B,B}(t)=\left(\begin{array}{c|c}I&Z\\ \hline\cr Z&Z\end{array}\right)

    in block partial-identity form.

Hefferon, Linear Algebra, Maps Between Spaces, Projection Into a Subspace, Exercise 19

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Adapted from Linear Algebra © 2016 Jim Hefferon. Licensed under CC BY-SA 3.0 US. Source: Linear Algebra. Imported at revision df2262e.