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Exercise 20

Avg difficulty 3.0

If we have nn data points (x1,y1),(x2,y2),… ,(xn,yn)(x_{1},y_{1}),(x_{2},y_{2}),\dots\,,(x_{n},y_{n}) and want to find a polynomial p(x)=an−1xn−1+an−2xn−2+⋯+a1x+a0p(x)=a_{n-1}x^{n-1}+a_{n-2}x^{n-2}+\dots+a_{1}x+a_{0} passing through those points then we can plug in the points to get an nn equation/nn unknown linear system. The matrix of coefficients for that system is the Vandermonde matrix. Prove that the determinant of the transpose of that matrix of coefficients

∣11…1x1x2…xnx12x22…xn2⋮x1n−1x2n−1…xnn−1∣\begin{vmatrix}1&1&\ldots&1\\ x_{1}&x_{2}&\ldots&x_{n}\\ {x_{1}}^{2}&{x_{2}}^{2}&\ldots&{x_{n}}^{2}\\ &\vdots\\ {x_{1}}^{n-1}&{x_{2}}^{n-1}&\ldots&{x_{n}}^{n-1}\end{vmatrix}

equals the product, over all indices i,j∈{1,…,n}i,j\in\text{$\{\hskip 1.00006pt1,\dots,n\hskip 1.00006pt\}$} with i<ji<j, of terms of the form xj−xix_{j}-x_{i}. (This shows that the determinant is zero, and the linear system has no solution, if and only if the xix_{i}’s in the data are not distinct.)

Hefferon, Linear Algebra, Determinants, The Permutation Expansion, Exercise 20

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Adapted from Linear Algebra © 2016 Jim Hefferon. Licensed under CC BY-SA 3.0 US. Source: Linear Algebra. Imported at revision df2262e.