AI Tutor
Back to Gauss-Jordan elimination

Exercise 1.5.7

Avg difficulty 3.0

Solve the following two systems of equations simultaneously, by using a single augmented matrix with two constant vectors.

x+2y−z = 0 2x+3y+z = 3 x−y+2z = 3 x+2y−z = 1 2x+3y+z = 7 x−y+2z = 4 \begin{array}{rcl}x+2y-z~{}&=~{}&0~{}\\ 2x+3y+z~{}&=~{}&3~{}\\ x-y+2z~{}&=~{}&3~{}\\ \end{array}\quad\quad\begin{array}{rcl}x+2y-z~{}&=~{}&1~{}\\ 2x+3y+z~{}&=~{}&7~{}\\ x-y+2z~{}&=~{}&4~{}\\ \end{array}

Selinger, Matrix Theory and Linear Algebra, Systems of linear equations, Gauss-Jordan elimination, Exercise 1.5.7

AI Tutor

Adapted from Matrix Theory and Linear Algebra © 2017–2026 Peter Selinger, Lyryx Learning, and Ken Kuttler. Licensed under CC BY 4.0. Source: Matrix Theory and Linear Algebra. Imported at revision d74bc3a.