Back to First-Order Linear Equations

Exercise 30

Avg difficulty 2.5

The differential equation dydt=y−4t+y2−8yt+16t2+4.\frac{dy}{dt} = y - 4t + y^2 - 8yt + 16 t^2 + 4. is not autonomous, separable, or linear; however, we can solve this equation with a change of variable.

  1. Transform this equation into a new differential equation of the form dudt=f(u)\frac{du}{dt}= f(u) by letting u=y−4tu = y - 4t.

  2. Sketch the phase line for this new equation, u′=f(u)u' = f(u), and sketch several solutions.

  3. Find the solutions of the original differential equation that correspond to the equilibrium solutions of u′=f(u)u' = f(u). Graph these solutions in tyty-plane. Also, sketch the graphs of the solutions that you plotted in part (b).

  4. Solve the differential new equation and use this information to solve the original differential equation.

Judson, The ODE Project, §1.5 First-Order Linear Equations, Exercise 30

AI Tutor

Adapted from The ODE Project © 2019–2025 Thomas W. Judson. Licensed under CC BY 4.0. Source: The ODE Project. Imported at revision 7935458.