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Exercise 10

Avg difficulty 2.5

Consider the linear system x′=x+3y+(t−3t2)y′=x−y+(2−t+t2)x(0)=1y(0)=−1.\begin{aligned} x' & = x + 3y + (t - 3t^2) \\ y' & = x - y + (2 - t + t^2) \\ x(0) & = 1 \\ y(0) & = -1. \end{aligned}

  1. Find the general solution of the homogeneous system x′=x+3yy′=x−y\begin{aligned} x' & = x + 3y \\ y' & = x - y \end{aligned}

  2. Find a particular solution for x′=x+3y+(t−3t2)y′=x−y+(2−t+t2)\begin{aligned} x' & = x + 3y + (t - 3t^2) \\ y' & = x - y + (2 - t + t^2) \end{aligned}

  3. Find the solution of x′=x+3y+(t−3t2)y′=x−y+(2−t+t2)x(0)=1y(0)=−1.\begin{aligned} x' & = x + 3y + (t - 3t^2) \\ y' & = x - y + (2 - t + t^2) \\ x(0) & = 1 \\ y(0) & = -1. \end{aligned}

Judson, The ODE Project, §3.2 Planar Systems, Exercise 10

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Adapted from The ODE Project © 2019–2025 Thomas W. Judson. Licensed under CC BY 4.0. Source: The ODE Project. Imported at revision 7935458.