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Exercise 21

Avg difficulty 2.5

Define the gamma function to be Γ(x)=∫0∞e−ttx−1  dt\Gamma(x) = \int_0^\infty e^{-t} t^{x-1} \; dt for x>0x \gt 0. The gamma function is very useful for expressing the Laplace transform of the function tαt^\alpha.

  1. Show that Γ(1)=1\Gamma(1) = 1.

  2. Prove that Γ(x+1)=xΓ(x)\Gamma(x + 1) = x\Gamma(x) and deduce that Γ(n+1)=n!\Gamma(n+1) = n! for n∈Nn \in {\mathbb N}.

  3. Show that the Laplace transform of f(t)=tαf(t) = t^\alpha is L(f)(s)=Γ(α+1)sα+1.{\mathcal L}(f)(s) = \frac{\Gamma(\alpha + 1)}{s^{\alpha + 1}}. If nn is a positive integer, then L(tn)(s)=n!/sn+1{\mathcal L}(t^n)(s) = n!/s^{n + 1}.

Judson, The ODE Project, §6.1 The Laplace Transform, Exercise 21

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Adapted from The ODE Project © 2019–2025 Thomas W. Judson. Licensed under CC BY 4.0. Source: The ODE Project. Imported at revision 7935458.