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Exercise 12

Avg difficulty 2.5

Let f(t)f(t) be a peicewise continuous function for t≥0t \geq 0. In addition, suppose that f(t)f(t)satisfies the condition ∣f(t)∣≤Mect|f(t)| \leq M e^{ct} with t≥0t \geq 0.

  1. Prove that L(∫0tf(τ) dτ)=1sL(f(t)=F(s)s.{\mathcal L} \left( \int_0^t f(\tau) \, d\tau \right) = \frac{1}{s} {\mathcal L}(f(t) = \frac{F(s)}{s}.

  2. Show that L−1(F(s)s)=∫0tf(τ) dτ{\mathcal L}^{-1} \left( \frac{F(s)}{s} \right) = \int_0^t f(\tau) \, d\tau follows from (a).

Judson, The ODE Project, §6.2 Solving Initial Value Problems, Exercise 12

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Adapted from The ODE Project © 2019–2025 Thomas W. Judson. Licensed under CC BY 4.0. Source: The ODE Project. Imported at revision 7935458.