Back to Linear independence

Exercise 10

Avg difficulty 2.5

Given a set of linearly dependent vectors, we can eliminate some of the vectors to create a smaller, linearly independent set of vectors.

  1. Suppose that w\wvec is a linear combination of the vectors v1\vvec_1 and v2\vvec_2. Explain why Span{v1,v2,w}=Span{v1,v2}\laspan{\vvec_1,\vvec_2, \wvec} = \laspan{\vvec_1,\vvec_2}.

  2. Consider the vectors v1=[2−10],v2=[121],v3=[−262],v4=[7−11]\vvec_1 = \threevec{2}{-1}{0}, \vvec_2 = \threevec{1}{2}{1}, \vvec_3 = \threevec{-2}{6}{2}, \vvec_4 = \threevec{7}{-1}{1}. Write one of the vectors as a linear combination of the others. Find a set of three vectors whose span is the same as Span{v1,v2,v3,v4}\laspan{\vvec_1,\vvec_2,\vvec_3,\vvec_4}.

  3. Are the three vectors you are left with linearly independent? If not, express one of the vectors as a linear combination of the others and find a set of two vectors whose span is the same as Span{v1,v2,v3,v4}\laspan{\vvec_1,\vvec_2,\vvec_3,\vvec_4}.

  4. Give a geometric description of Span{v1,v2,v3,v4}\laspan{\vvec_1,\vvec_2,\vvec_3,\vvec_4} in R3\real^3 as we did in The span of a set of vectors.

Austin, Understanding Linear Algebra, §2.4 Linear independence, Exercise 10

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Adapted from Understanding Linear Algebra © 2023 David Austin. Licensed under CC BY 4.0. Source: Understanding Linear Algebra. Imported at revision 3e6dced.