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Exercise 6

Avg difficulty 2.5

We say that AA is similar to BB if there is a matrix PP such that A=PBP−1A = PBP^{-1}.

  1. If AA is similar to BB, explain why BB is similar to AA.

  2. If AA is similar to BB and BB is similar to CC, explain why AA is similar to CC.

  3. If AA is similar to BB and BB is diagonalizable, explain why AA is diagonalizable.

  4. If AA and BB are similar, explain why AA and BB have the same characteristic polynomial; that is, explain why det⁡(A−λI)=det⁡(B−λI)\det(A-\lambda I) = \det(B-\lambda I).

  5. If AA and BB are similar, explain why AA and BB have the same eigenvalues.

Austin, Understanding Linear Algebra, §4.3 Diagonalization, similarity, and powers of a matrix, Exercise 6

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Adapted from Understanding Linear Algebra © 2023 David Austin. Licensed under CC BY 4.0. Source: Understanding Linear Algebra. Imported at revision 3e6dced.