Back to Singular Value Decompositions

Exercise 11

Avg difficulty 2.5

Suppose that A=UΣVTA=U\Sigma V^T is a singular value decomposition of the m×nm\times n matrix AA. If σ1,…,σr\sigma_1,\ldots,\sigma_r are the nonzero singular values, the general form of the matrix Σ\Sigma is Σ=[σ1…0…00…0…00…σr…00…0…00⋮0⋮00…0…0].\Sigma = \begin{bmatrix} \sigma_1 & \ldots & 0 & \ldots & 0 \\ 0 & \ldots & 0 & \ldots & 0 \\ 0 & \ldots & \sigma_r & \ldots & 0 \\ 0 & \ldots & 0 & \ldots & 0 \\ 0 & \vdots & 0 & \vdots & 0 \\ 0 & \ldots & 0 & \ldots & 0 \\ \end{bmatrix}.

  1. If you know that the columns of AA are linearly independent, what more can you say about the form of Σ\Sigma?

  2. If you know that the columns of AA span Rm\real^m, what more can you say about the form of Σ\Sigma?

  3. If you know that the columns of AA are linearly independent and span Rm\real^m, what more can you say about the form of Σ\Sigma?

Austin, Understanding Linear Algebra, §7.4 Singular Value Decompositions, Exercise 11

AI Tutor

Adapted from Understanding Linear Algebra © 2023 David Austin. Licensed under CC BY 4.0. Source: Understanding Linear Algebra. Imported at revision 3e6dced.