Back to 4.2 Acceleration Vector

4.2 Exercise 8

Avg difficulty 2.5

The position of a particle for t > 0 is given by r→(t)=(3.0t2i^−7.0t3j^−5.0t−2k^)m.\overset{\rightarrow}{r} \left(t\right) = \left(3.0 t^{2} \hat{i} - 7.0 t^{3} \hat{j} - 5.0 t^{−2} \hat{k}\right) \text{m} . (a) What is the velocity as a function of time? (b) What is the acceleration as a function of time? (c) What is the particle’s velocity at t = 2.0 s? (d) What is its speed at t = 1.0 s and t = 3.0 s? (e) What is the average velocity between t = 1.0 s and t = 2.0 s?

OpenStax University Physics Volume 1, 4.2 Acceleration Vector, exercise 8

AI Tutor

Adapted from University Physics Volume 1 © 2016 Rice University. Licensed under CC BY 4.0. Source: University Physics Volume 1. Imported at revision db44eb9.