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9.1 Exercise 10

Avg difficulty 2.5

The quantity of charge through a conductor is modeled as Q=4.00Cs4t4−1.00Cst+6.00mCQ = 4.00 \frac{\text{C}}{\text{s}^{4}} t^{4} - 1.00 \frac{\text{C}}{\text{s}} t + 6.00 \text{mC}.

What is the current at time t=3.00st = 3.00 \text{s}?

OpenStax University Physics Volume 2, 9.1 Electrical Current, exercise 10

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Adapted from University Physics Volume 2 © 2016 Rice University. Licensed under CC BY 4.0. Source: University Physics Volume 2. Imported at revision db44eb9.