7.6 Exercise 42

An electron has an initial velocity of $5.00 \times 10^{6} \text{m}/\text{s}$ in a uniform $2.00 \times 10^{5} -\text{N}/\text{C}$ electric field. The field accelerates the electron in the direction opposite to its initial velocity. (a) What is the direction of the electric field? (b) How far does the electron travel before coming to rest? (c) How long does it take the electron to come to rest? (d) What is the electron’s velocity when it returns to its starting point?