Back to 7.2 Electric Potential and Potential Difference

7.2 Exercise 18

Avg difficulty 2.5

The electric field strength between two parallel conducting plates separated by 4.00 cm is 7.50×104V/m7.50 \times 10^{4} \text{V}/\text{m}. (a) What is the potential difference between the plates? (b) The plate with the lowest potential is taken to be zero volts. What is the potential 1.00 cm from that plate and 3.00 cm from the other?

OpenStax University Physics Volume 2, 7.2 Electric Potential and Potential Difference, exercise 18

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Adapted from University Physics Volume 2 © 2016 Rice University. Licensed under CC BY 4.0. Source: University Physics Volume 2. Imported at revision db44eb9.