Back to 11.3 Motion of a Charged Particle in a Magnetic Field

11.3 Exercise 13

Avg difficulty 2.5

An alpha-particle (m=6.64×10−27kg,\left(\right. m = 6.64 \times 10^{−27} \text{kg}, q=3.2×10−19C)q = 3.2 \times 10^{−19} \text{C} \left.\right) travels in a circular path of radius 25 cm in a uniform magnetic field of magnitude 1.5 T. (a) What is the speed of the particle? (b) What is the kinetic energy in electron-volts? (c) Through what potential difference must the particle be accelerated in order to give it this kinetic energy?

OpenStax University Physics Volume 2, 11.3 Motion of a Charged Particle in a Magnetic Field, exercise 13

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Adapted from University Physics Volume 2 © 2016 Rice University. Licensed under CC BY 4.0. Source: University Physics Volume 2. Imported at revision db44eb9.