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3.6 Exercise 27

Avg difficulty 2.5

In an adiabatic process, oxygen gas in a container is compressed along a path that can be described by the following pressure in atm as a function of volume V, with V0=1LV_{0} = 1 L: p=(3.0atm)(V/V0)−1.2p = \left(3.0 \text{atm}\right) \left(\right. V / V_{0} \left.\right)^{−1.2}. The initial and final volumes during the process were 2 L and 1.5 L, respectively. Find the amount of work done on the gas.

OpenStax University Physics Volume 2, 3.6 Adiabatic Processes for an Ideal Gas, exercise 27

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Adapted from University Physics Volume 2 © 2016 Rice University. Licensed under CC BY 4.0. Source: University Physics Volume 2. Imported at revision db44eb9.