Back to 9.8 Superconductivity

9.8 Exercise 10

Avg difficulty 2.5

Potassium fluoride (KF) is a molecule formed by an ionic bond. At equilibrium separation the atoms are r0=0.255nmr_{0} = 0.255 \text{nm} apart. Determine the electrostatic potential energy of the atoms. The electron affinity of F is 3.40 eV and the ionization energy of K is 4.34 eV. Determine dissociation energy. (Neglect the energy of repulsion.)

OpenStax University Physics Volume 3, 9.8 Superconductivity, exercise 10

AI Tutor

Adapted from University Physics Volume 3 © 2016 Rice University. Licensed under CC BY 4.0. Source: University Physics Volume 3. Imported at revision db44eb9.